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TPA2000D1 データシート(PDF) 10 Page - Texas Instruments |
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TPA2000D1 データシート(HTML) 10 Page - Texas Instruments |
10 / 20 page www.ti.com 0 V –5 V +5 V Current OUTP OUTN Differential Voltage Across Load 0 V –5 V +5 V Current OUTP OUTN Differential Voltage Across Load Output = 0 V Output > 0 V EFFICIENCY: WHY YOU MUST USE A FILTER WITH THE TRADITIONAL CLASS-D MODULATION TPA2000D1 SLOS328F – JUNE 2000 – REVISED MARCH 2004 APPLICATION INFORMATION (continued) Figure 10. The TPA2000D1 Output Voltage and Current Waveforms Into an Inductive Load SCHEME The main reason that the traditional class-D amplifier needs an output filter is that the switching waveform results in maximum current flow. This causes more loss in the load, which causes lower efficiency. The ripple current is large for the traditional modulation scheme because the ripple current is proportional to voltage multiplied by the time at that voltage. The differential voltage swing is 2 × V DD and the time at each voltage is half the period for the traditional modulation scheme. An ideal LC filter is needed to store the ripple current from each half cycle for the next half cycle, while any resistance causes power dissipation. The speaker is both resistive and reactive, whereas an LC filter is almost purely reactive. The TPA2000D1 modulation scheme has little loss in the load without a filter because the pulses are short and the change in voltage is VDD instead of 2 × VDD. As the output power increases, the pulses widen making the ripple current larger. Ripple current could be filtered with an LC filter for increased efficiency, but for most applications the filter is not needed. An LC filter with a cutoff frequency less than the class-D switching frequency allows the switching current to flow through the filter instead of the load. The filter has less resistance than the speaker that results in less power dissipated, which increases efficiency. 10 |
同様の部品番号 - TPA2000D1_06 |
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同様の説明 - TPA2000D1_06 |
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