TDA8591 datasheet(11/36 Pages) PHILIPS

部品番号	TDA8591

部品情報	4 X 44 W into 4 or 4 X 75 W into 2 quad BTL car radio power amplifier

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メーカー	PHILIPS [NXP Semiconductors]

ホームページ	http://www.nxp.com

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11 / 36 page

2002 Jan 14

11

Philips Semiconductors

Preliminary speciﬁcation

4

× 44 W into 4 Ω or 4 × 75 W into 2 Ω

quad BTL car radio power ampliﬁer

TDA8591J

7.3

Mute timer and single-pin mute control

The transition time from mute mode to operating mode can

be used to hide plops that occur during switching. This

transition time is determined by the value of the external

capacitor at the MUTE/ON input (see Fig.33). To

guarantee the mute suppression, the resistor value may

not be more than 15 k

Ω. The switching can be controlled

by a transistor switch with an open-drain output or a

voltage output with a minimum high level of 5.5 V.

When controlling with an open-drain output, the high

voltage level also must be at least 5.5 V and should not be

clamped on a lower value by the ESD diode of the

microcontroller. If the minimum high voltage cannot be

guaranteed, an external open-drain transistor or switch to

ground can be used. Charging of the external capacitor at

the MUTE/ON input is done by an internal current source.

If muting is performed by the microcontroller, the mute

connection to the microcontroller can be omitted. The

mute on and off transitions during start-up and switch-off

are controlled by an internal push-pull current source and

the external capacitor at pin 8 (MUTE/ON).

Fast mute can be achieved by quickly discharging the

mute capacitor by means of an open-drain transistor

without a series resistor.

7.4

Output power

EIAJ power is a power rating which indicates the maximum

possible output power of a specific application at a nominal

supply voltage. The power losses caused by PCB layout,

copper area, connector block, coil, loudspeaker wires, etc.

depend on the applications.

Therefore, the EIAJ power is defined and measured at the

pins of the IC using the following test conditions:

• The supply voltage is 14.4 V measured on the pins of

the TDA8591J

• All channels are loaded with 4 Ω and are driven

simultaneously

• The input signal is a continuous (no burst) square wave:

V = 1 V (RMS); f = 1 kHz

• RMS output power is measured immediately at the start

(cold heatsink) and after 1 minute of operation. The

mean value is the rated EIAJ power.

To have optimum output power performance, the external

heatsink should be chosen carefully. A small heatsink

causes a high junction temperature, resulting in an

increase of the drain-source on-state resistance (RDSon)of

the power amplifiers and a decrease of the maximum

output power.

The reason for using a square wave input signal for EIAJ

power measurement is illustrated in Fig.9.

Figure 9a shows a square wave signal with

Assuming this square wave is the output signal of an

amplifier, the EIAJ output power is given by

where:

RL = load resistor in Ω

Vtop = maximum voltage across the load in V

f = frequency of the square wave in Hz

tr = rise time of the slope in s.

A sine wave has a lower slew rate than a square wave as

shown in Fig.9b, therefore EIAJ power measurement with

a sine wave will give a lower power value. The maximum

slew rate of a sine wave output signal is given by

where:

A = amplitude of the output sinewave in V

f = frequency of the output sinewave in Hz.

For a non-clipping sinewave output with amplitude

A = 13 V and frequency f = 1 kHz, the slew rate is

A faster slew rate can be obtained by increasing the

amplitude: for an amplitude of 28 V, the slew rate will

increase to 1.85 V/s. A supply voltage of VP = 14.4 V will

result in a clipped output with a shape similar to a square

wave but with a slower slew rate.

Figure 9c shows the dependency of PEIAJ on slew rate.

Using a square wave input signal, the EIAJ output power

is determined by the drop voltage and bandwidth of the

output stage.

slew rate

V

top

t

r

----------

=

P

EIAJ

V

top

2

R

L

-------------

1

8

3

---



 V

top

×

f

×

–

slew rate

-------------------------------------------

×

=

δU

out

δt max

------------------

δ A sin

×

2

πft

×

()

δt max

------------------------------------------------

2

πfA

×

==

δU

out

δt max

------------------

82

3

V/s

=

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